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infinite geometric progression = A/(1-R) where a = square of (1/4)= 1/16 and R = 1/4
Area of shaded region = (1/16)/(1-1/4) = 1/12
Ratio = (1-(1/12))/1 = 11/12
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August 2nd, 2011 at 7:33 am
infinite geometric progression = A/(1-R)
where a = square of (1/4)= 1/16 and R = 1/4
Area of shaded region = (1/16)/(1-1/4) = 1/12
Ratio = (1-(1/12))/1 = 11/12